# 2018 JAMB Mathematics Past Questions & Answers - page 1

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1

In a class of 40 students, 32 offer Mathematics, 24 offer Physics and 4 offer neither Mathematics nor Physics. How many offer both Mathematics and Physics?

A 4
B 8
C 16
D 20

Correct Option: D

2

Find the values of x for which

$$\frac {x+2}{4}$$ - $$\frac{2x - 3}{3}$$ < 4

A x < 8
B x > -6
C x < 4
D x > -3

Correct Option: B

3

Find \N\

A 65
B 23
C 17
D 91

Correct Option: C

4

If X, Y can take values from the set (1, 2, 3 ,4), find the probability that the product of X and Y is not greater than 6

A $$\frac{5}{8}$$
B $$\frac{5}{16}$$
C $$\frac{1}{2}$$
D $$\frac{3}{8}$$

Correct Option: D

Solution

Pr(product of x and y NOT > 6 ) = $$\frac{8}{16}$$ = $$\frac{1}{2}$$

5

The pie chart shows the monthly expenditure of a public servant. The monthly expenditure on housing is twice that of school fees. How much does the worker spend on housing if his monthly income is N7200?

A 1000
B 2000
C 3000
D 4000

Correct Option: B

6

Evaluate 5$$^{-3}$$ log$$^2$$ x 2 $$^{2 \log 3}$$

A 8
B A. $$\frac{1}{8}$$
C B. 1$$\frac{1}{8}$$
D C. $$\frac{2}{5}$$

Correct Option: B

7

A trader realises 10x - x$$^2$$ Naira profit from the sale of x bags of corn. How many bags will give him the maximum profit?

A 7
B 6
C 5
D 4

Correct Option: C

Solution

Profit (P) = 10$$_x$$ − $$_x$$2

At max profit, the differential of profit with respect to number of bags(x) = 0

Hence,

$$\frac{dp}{dx}$$ = 0

$$\frac{dp}{dx}$$ = 10 - 2x = 0

10 = 2x

Then x = $$\frac{10}{2}$$ = 5

8

If y = 23$$_{five}$$ 101$$_{three}$$ , find y, leaving your answer in base two

A 1110
B 10111
C 11101
D 111100

Correct Option: B

9

Find the value of x in the diagram

A 10°
B 28°
C 36°
D 40°

Correct Option: D

Solution

Total angle at a point = 360

x - 10 + 4x - 50 + 2x + 3x + 20 = 360

10x - 40 = 360

10x = 360 + 40

10x = 400

x = $$\frac{400}{10}$$

x = 40

10

Solve for t in the equation $$\frac{3}{4}$$t + $$\frac{1}{3}$$(21 - t) = 11

A $$\frac{9}{13}$$
B $$\frac{7}{13}$$
C 5
D 9$$\frac{3}{5}$$

Correct Option: D

Solution

$$\frac{3}{4}$$ t + $$\frac{1}{3}$$ (21 - t) = 11

Multiply through by the LCM of 4 and 3 which, that is 12

12 x($$\frac{3}{4}$$ t) + 12 x ($$\frac{1}{3}$$ (21 - t)) = (11 x 12)

9t + 4(21 - t) = 132

9t + 84 - 4t = 132

5t + 84 = 132

5t = 132 - 84 = 48

t = $$\frac{48}{5}$$

t = 9 $$\frac{3}{5}$$

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