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1995 - JAMB Mathematics Past Questions and Answers - page 4

31

For what value of x is the tangent to the curve y = x2 - 4x + 3 parallel to the x-axis?

A
3
B
2
C
1
D
6
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32

Two variables x and y are such that (\frac{dy}{dx}) = 4x - 3 and y = 5 when x = 2. Find y in terms of x

A
2x2 - 3x + 5
B
2x2 - 3x + 3
C
2x2 - 3x
D
4
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33

Find the area bounded by the curve y = 3x2 - 2x + 1, the ordinates x = 1 and x = 3 and the a-axix

A
24
B
22
C
21
D
20
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34

(\begin{array}{c|c} \text{Age in years} & 13 & 14 & 15 & 16 & 17 \ \hline \text{No. of students} & 3 & 10 & 30 & 42 & 15\end{array})

The frequency distribution above shows the ages of students in a secondary school. In a pie chart constructed to represent the data, the angles corresponding to the 15 years old is

A
27o
B
30o
C
54o
D
108o
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35

The pie chart shows the distribution of students in a secondary school class. If 30 students offered French, how many offered C.R.K?

A
25
B
15
C
10
D
8
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36

(\begin{array}{c|c} class& 1 - 3 & 4 - 6 & 7 - 9\ \hline Frequency & 5 & 8 & 5\end{array})

Find the standard deviation of the data using the table above

A
5
B
\(\sqrt{6}\0
C
\(\frac{5}{3}\)
D
\(\sqrt{5}\)
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37

The variance of the scores 1, 2, 3, 4, 5 is

A
1, 2
B
1, 4
C
2.0
D
3.0
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38

(\begin{array}{c|c} \text{Class Interval} & Frequency & \text{Class boundaries} & Class Mid-point \ \hline 1.5 - 1.9 & 2 & 1.45 - 1.95 & 1.7\ 2.0 - 2.4 & 21 & 1.95 - 2.45 & 2.2\ 2.5 - 2.9 & 4 & 2.45 - 2.95 & 2.7 \ 3.0 - 2.9 & 15 & 2.95 - 3.45 & 3.2\ 3.5 - 3.9 & 10 & 3.45 - 3.95 & 3.7\ 4.0 - 4.4 & 5 & 3.95 - 4.45 & 4.2\ 4.5 - 4.9 & 3 & 4.45 - 4.95 & 4.7\end{array})

Find the mode of the distribution above to find the mode of the distribution.

A
3.2
B
3.3
C
3.7
D
4.2
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39

(\begin{array}{c|c} \text{Class Interval} & Frequency & \text{Class boundaries} & Class Mid-point \ \hline 1.5 - 1.9 & 2 & 1.45 - 1.95 & 1.7\ 2.0 - 2.4 & 21 & 1.95 - 2.45 & 2.2\ 2.5 - 2.9 & 4 & 2.45 - 2.95 & 2.7 \ 3.0 - 2.9 & 15 & 2.95 - 3.45 & 3.2\ 3.5 - 3.9 & 10 & 3.45 - 3.95 & 3.7\ 4.0 - 4.4 & 5 & 3.95 - 4.45 & 4.2\ 4.5 - 4.9 & 3 & 4.45 - 4.95 & 4.7\end{array})

The median of the distribution above is

A
4.0
B
3.4
C
3.2
D
3.0
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40

Let p be a probability function on set S, where S = (a1, a2, a3, a4). Find P(a1) if P(a2) = (\frac{1}{3}), p(a3) = (\frac{1}{6}) and p(a4) = (\frac{1}{5})

A
\(\frac{7}{3}\)
B
\(\frac{2}{3}\)
C
\(\frac{1}{3}\)
D
\(\frac{3}{10}\)
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