2022 - JAMB Mathematics Past Questions and Answers - page 4

hyp = 5cm, adj =  \(\frac{8cm}{2}\) 4cm, opp = xcm

Appy Pythagoras' theorem: 

hyp\(^2\) = opp\(^2\) + adj\(^2\)

5\(^2\) = x\(^2\) + 4\(^2\)

x\(^2\) = 25 - 16

x = √9

x = 3cm

3 * 5 = 3 - 5 + (3 x 5)\(^2\)

-2 + (15)\(^2\)

-2 + 225 

= 223

Given that y is inversely proportional to x,

y = 1/x; y = \(\frac{k}{x}\)

k =xy → 3 * 4 = 12

x = \(\frac{k}{y}\) 

x = \(\frac{12}{12}\) = 1

Common difference = 6

Hence, add 6 to get the next terms:

8, 14, 20 and 26

Mean (4) =  \(\frac{2x + 4x + 2x - 13 + 6x}{4}\)

16 = 14x - 13

16 + 13 = 14x

x = 29/14 or 2.07

Trial:

(2a-3b) (2a+3b)

4a\(^2\) + 6ab - 6ab - 9b\(^2\)

4a\(^2\) - 9b\(^2\)

n(PuQ) = n(p) + n(q) -  n(PnQ)

40 = 20 + 30 -  n(PnQ)

n(PnQ) = 50 - 40 = 10

• three times a certain number (x) => 3x
• minus 2 = -2
• is less than = <
• the number minus 6 = x -6

Hence; 3x - 2 < x - 6

3x - x < -6 + 2

2x < -4

x < -2 is the possible value of x

The arrow points in the direction of all numbers greater than 2

Hence,

x ≥ 2 

Given that the cost of the dress reduces to #3800.00 by the discount,

Assume the original price = x

x – (20% of x) = 100

x – 0.2x = 100

0.8x = #3800

x = \(\frac{3800}{0.8}\)

x = 4,750