Acids, Bases, and pH - SS2 Chemistry Past Questions and Answers - page 2

To calculate the pH from the hydrogen ion concentration, we use the equation pH = -log[H+]. Taking the logarithm (base 10) of 10^-12, we find that the pH is 12.

The pH of a solution can be calculated using the formula:

pH = -log[H+]

Given that the hydrogen ion concentration ([H+]) is 1 x 10^-3 M, we can substitute this value into the formula:

pH = -log(1 x 10^-3)

pH = -(-3) = 3

Therefore, the pH of the solution is 3.

The hydrogen ion concentration can be calculated by taking the antilog of the negative pH value:

[H+] = 10^(-pH)

Given that the pH is 9, we can substitute this value into the formula:

[H+] = 10^(-9)

[H+] = 1 x 10^(-9)

Therefore, the hydrogen ion concentration of the solution is 1 x 10^(-9) M.

To calculate the pH of a solution based on the hydroxide ion concentration, we can use the pOH formula:

pOH = -log[OH-]

Since pH + pOH = 14 (at 25°C), we can subtract the pOH value from 14 to obtain the pH:

pH = 14 - pOH

Given that the hydroxide ion concentration ([OH-]) is 1 x 10^-11 M, we can calculate the pOH:

pOH = -log(1 x 10^-11) = 11

Substituting the pOH value into the pH formula:

pH = 14 - 11 = 3

Therefore, the pH of the solution is 3.

To calculate the pH of a solution based on the hydroxide ion concentration, we can use the pOH formula:

pOH = -log[OH-]

Since pH + pOH = 14 (at 25°C), we can subtract the pOH value from 14 to obtain the pH:

pH = 14 - pOH

Given that the hydroxide ion concentration ([OH-]) is 1 x 10^-11 M, we can calculate the pOH:

pOH = -log(1 x 10^-11) = 11

Substituting the pOH value into the pH formula:

pH = 14 - 11 = 3

Therefore, the pH of the solution is 3.