2002 - WAEC Mathematics Past Questions and Answers - page 3

21

For what values of x is the expression \(\frac{3x-2}{4x^2+9x-9}\) undefined?

A
\(\frac{-3}{4} \hspace{1mm}or \hspace{1mm}3\)
B
\(\frac{-2}{3} \hspace{1mm}or \hspace{1mm}-3\)
C
\(\frac{2}{3} \hspace{1mm}or \hspace{1mm}3\)
D
\(\frac{3}{4} \hspace{1mm}or \hspace{1mm}-3\)
correct option: d

The equation \(\frac{3x - 2}{4x^2 + 9x - 9}\) is undefined when the denominator = 0.

\(4x^2 + 9x - 9 = 0\)

\(4x^2 + 12x - 3x - 9 = 0\)

\(4x(x + 3) - 3(x + 3) = 0\)

\((4x - 3)(x + 3) = 0\)

x = \(\frac{3}{4}\) or x = -3.

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22
Simplify \(\frac{1}{1-x} + \frac{2}{1+x}\)
A
\(\frac{x+3}{1-x^2}\)
B
\(\frac{x-3}{1+x^2}\)
C
\(\frac{3-x}{1-x^2}\)
D
\(\frac{3-x}{1+x^2}\)
correct option: c
\(\frac{1}{1-x} + \frac{2}{1+x}\
\frac{1+x+2-2x}{(1-x)(1+x)} = \(\frac{3-x}{1-x^2}\)\)
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23
The lengths of the parallel sides of a trapezium are 9 cm and 12 cm. lf the area of the trapezium is 105 cm2, find the perpendicular distance between the parallel sides.
A
5cm
B
7cm
C
10cm
D
15cm
correct option: c
\(\frac{1}{2}(a+b)\times h = 105cm^2\
\frac{1}{2}(9+12)\times h = 105\
h = \frac{105 \times 2}{21} = 10cm\)
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24
The base diameter of a cone is 14cm, and its volume is 462 cm3. Find its height. [Taken \(\pi = \frac{22}{7}\)]
A
3.5cm
B
5cm
C
7cm
D
9cm
correct option: d
From \(V = \frac{1}{3}\pi r^2 h. \hspace{1mm} r =\frac{14}{2}\
462 = \frac{1}{3} \times \frac{22}{7} \times 7^2 \times h \
h = \frac{3 \times 462}{22 \times 7}\ h = 9\)
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25

A number is selected at random from the set Y = {18, 19, 20, . . . 28, 29}. Find the probability that the number is prime.

A
\(\frac{1}{4}\)
B
\(\frac{3}{11}\)
C
\(\frac{1}{2}\)
D
\(\frac{3}{4}\)
correct option: a

Y = {18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29}

Number of prime numbers = 3

Prob(picking  a prime number) = \(\frac{3}{12}\)

= \(\frac{1}{4}\)

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26
The median of the distribution is
A
25
B
17.5
C
15
D
12.5
correct option: c
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27
The range of the distribution is
A
50
B
30
C
25
D
15
correct option: c
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28
The upper quartile of the distribution is
A
30
B
27.5
C
25
D
17.75
correct option: d
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29

In the diagram O and O' are the centres of the circles radii 15cm and 8cm respectively. If PQ = 12cm, find |OO'|.

A
8.46cm
B
19.04cm
C
20.81cm
D
26.16cm
correct option: b

 In \(\Delta\) POQ, 

\(12^2 = 15^2 + 15^2 - 2(15)(15) \cos < POQ\)

\(144 = 450 - 450\cos < POQ\)

\(450 \cos < POQ = 450 - 144 = 306\)

\(\cos <POQ = \frac{306}{450} = 0.68\)

\(< POQ = 47.2°\)

In \(\Delta\) PO'Q, 

\(12^2 = 8^2 + 8^2 - 2(8)(8) \cos <PO'Q\)

\(144 - 128 = -128 \cos < PO'Q\)

\(\cos < PO'Q = - 0.125\)

\(< PO'Q = 97.2°\)

In \(\Delta\) POQ,

\(\cos 23.6 = \frac{x}{15}\)

\(x = 15 \times \cos 23.6\)

= 13.75 cm

In \(\Delta\) PO'Q, 

\(\cos 48.6 = \frac{y}{8}\)

\(y = 8 \times \cos 48.6\)

= 5.29 cm

\(\therefore\) OO' = x + y = 13.75 + 5.29

= 19.04 cm

 

 

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30
In the diagram O is the centre of the circle. Which of the following is/are not true? I. a = b II. b + c = 180o III. a + b = c
A
I and II only
B
II and III only
C
II only
D
III only
correct option: a
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