2007 - WAEC Mathematics Past Questions and Answers - page 3
p (\alpha \frac{I}{Q}); p (\frac{k}{q}) (where k is constant)
q = (\frac{k}{p})
q (\alpha \frac{1}{p})
3 (\sqrt{45} - 12\sqrt{5} + 16\sqrt{20})
= 3 x (\sqrt{9 \times 5} - 12 \times \sqrt{5} + 16 \times \sqrt{4 \times 5})
= 3 x 3 x (\sqrt{5} - 12 \times \sqrt{5} + 16 \times 2 \times \sqrt{5})
= 9(\sqrt{5} - 2 \sqrt{5} + 32 \sqrt{5})
= 9(\sqrt{5} + 32\sqrt{5} - 12\sqrt{5})
= 29(\sqrt{5})
p = {-3.2.....4.9}; Since x is an integer
least value of x is -3
(\frac{3x^3}{(3x)^3}) = (\frac{3 \times x^3}{3^3 \times x^3})
= (\frac{3 \times x^3}{3 \times 3 \times 3 \times x^3})
= (\frac{1}{3^2})
= (\frac{1}{9})
Let Abu's share = 2x;
Kayode's = x
Uche's share = (\frac{x}{2})
Total: 2x + x + (\frac{x}{2}) = N140,000
(\frac{7x}{2}) = N140,000
x = (\frac{280,000}{7}) = N40,000
Kayode's share = N40,000
I am x years old; My brother = 3 + x; My brother
last year = (3 + x) - 1 = x + 3 - 1
= (x + 2) years
x = 3, y = 2, z = 4
3x2 - 2y + z
= 3(3)2 - 2(2) + 4
3(9) - 4 + 4 = 27
x + y = 2........... (i)
3x - 2y = 1......(ii)
From (i): x = 2 - y ..........(iii)
subt. (2 - y) for x in (ii)
3(2 - y) 2y = 1
6 - 3y - 2y = 1
-5y = 1 - 6 = -5
y = (\frac{-5}{-5}) = 1
subst. (i) for y in (iii)
x = 2 - 1 = 1
x = 1, y = 1
8x-1 = (\frac{1}{4})
23(x - 1 = 2-2
3x - 3 = -2
3x = -2 + 3
3x = 1
x = (\frac{1}{3})