2014 - WAEC Mathematics Past Questions and Answers - page 1

10(\frac{2}{5} - 6 \frac{2}{3} + 3)

(\frac{52}{5} - \frac{20}{3} + \frac{3}{1})

= (\frac{156 - 100 + 45}{15})

(\frac{156 + 45 - 100}{15})

= (\frac{201 - 100}{15})

= (\frac{101}{15})

= 6(\frac{11}{15})

23_x = 32₅

2 (\times x^1 + 3 \times x^0 = 3 \times 5^1 + 2 \times 5^0)

= 2x + 3 = 15 + 2

2x + 3 = 17

2x = 17 - 3

2x = 14

x = (\frac{14}{2})

x = 7

volume of cube = L x L x L

512cm³ = L³

L³ = 512cm³

L = 3(\sqrt{512})

L (512)^{(\frac{1}{3})}

= (2⁹)^{(\frac{1}{3})}

2³ = 8cm

at most 2 marks = 5 + 2 + 4 students = 11 students

probability(at most 2 marks) = (\frac{11}{20})

(\sqrt{12} ( \sqrt{48} - \sqrt{3}))

(\sqrt{4 \times 3} (6 \times 3 - \sqrt{3}) = 2 \sqrt{3}(4 \sqrt{3} - \sqrt{3}))

= 2(\sqrt{3} \times \sqrt{3} (4 - 1) 2\sqrt{9}(3) = 2 \times 3 \times 3 = 18)

x > y and 3 < y; then 3 < y means that y > 3

x > 3 to give the possible

x > y > 3

let the number be x

2(\frac{1}{2}x + \frac{3}{4}x = 13)

(\frac{5}{2}x + \frac{3}{4}x = 13)

multiply through by 4

4((\frac{5}{2}))x + 4((\frac{3}{4}))x = 13 x 4

2(5x) + 3x = 52

10x + 3x = 52

13x = 52

x = (\frac{52}{13})

x = 4

x = {0, 2, 4, 6}; y = {1, 2, 3, 4}; z = {1, 3}

u = {0, 1, 2, 3, 4, 5, 6}

y' = {0, 5, 6}

to find x (\cap) (Y' (\cup) Z)

first find y' (\cup) z = {0, 1, 3, 5, 6}

then x (\cap) (Y' (\cup) Z) = {0, 6}

x² = 3(2x + 9)

x² = 6x + 27

x² - 6x - 27 = 0

x² - 9x + 3x - 27 = 0

x(x - 9) + 3(x - 9) = (x + 3)(x - 9) = 0

x + 3 = 0 or x - 9 = 0

x = -3 or x = 9

x = -3, x = 9

p(4, 3) Q(2 - 1)

distance = (\sqrt{(x_2 - x_1)^2 + (Y_2 - y_1)^2})

= (\sqrt{(2 - 4)^2 + (-1 - 3)^2})

= (\sqrt{(-2)^2 = (-4)^2})

= (\sqrt{4 + 16})

= (\sqrt{20})

= (\sqrt{4 \times 5})

= 2(\sqrt{5})