2015 - WAEC Mathematics Past Questions & Answers - page 1

1
If {X: 2 d- x d- 19; X integer} and 7 + x = 4 (mod 9), find the highest value of x
A
2
B
5
C
15
D
18
CORRECT OPTION: c
2
The sum 110112, 11112 and 10m10n02. Find the value of m and n.
A
m = 0, n = 0
B
m = 1, n = 0
C
m = 0, n = 1
D
m = 1, n = 1
CORRECT OPTION: c
3

A trader bought an engine for $15,000.00 outside Nigeria. If the exchange rate is $0.075 to N1.00, how much did the engine cost in Naira?

A
N250,000.00
B
N200,000.00
C
N150,000.00
D
N100,000.00
CORRECT OPTION: b

N1.00 = $0.075

N X = $15,000

X = \(\frac{1.00 \times 15000}{0.075}\)

= N200,000.00

4
If \(\frac{27^x \times 3^{1 - x}}{9^{2x}} = 1\), find the value of x.
A
1
B
\(\frac{1}{2}\)
C
-\(\frac{1}{2}\)
D
-1
CORRECT OPTION: b
\(\frac{27^x \times 3^{1 - x}}{9^{2x}} = 1\)

\(\frac{3^{3x} \times 3^{1 - x}}{3^{2(2 - x)}} = 3^0\)

\(3^{3x} \times 3^{1 - x} \div 3^{4x} = 3^0\)

\(3^{(3x + 1 - x - 4x)} = 3^0\)

\(3^{(1 - 2x)} = 3^0\)

since the bases are equal,

1 - 2x = 0

- 2x = -1

x = \(\frac{1}{2}\)
5
Find the 7th term of the sequence: 2, 5, 10, 17, 6,...
A
37
B
48
C
50
D
63
CORRECT OPTION: c
6
Given that logx 64 = 3, evaluate x log8
A
6
B
9
C
12
D
24
CORRECT OPTION: c
If logx 64 = 3, then 64 = x3

43 = x3

Since the indices are equal,

x = 4

Hence, x log28 = log28x

= log284

= log2(23)4

= log2212

= 1 log2 = 1(1)

= 12
7
If 2n = y, Find 2\(^{(2 + \frac{n}{3})}\)
A
4y\(^\frac{1}{3}\)
B
4y\(^-3\)
C
2y\(^\frac{1}{3}\)
D
2y\(^-3\)
CORRECT OPTION: a
If 2n = y,

then, 2\(^{(2 + \frac{n}{3})}\) = 22 x 2\(^\frac{n}{3}\)

= 4 x (2n)\(^{\frac{1}{3}}\)

But y = 2n, hence

2\(^{(2 + \frac{n}{3})}\) = 4 x y\(^{\frac{1}{3}}\)

= 4y\(^\frac{1}{3}\)
8
Factorize completely: 6ax - 12by - 9ay + 8bx
A
(2a - 3b)(4x + 3y)
B
(3a + 4b)(2x - 3y)
C
(3a - 4b)(2x + 3y)
D
(2a + 3b)(4x -3y)
CORRECT OPTION: b
6ax - 12by - 9ay + 8bx

= 6ax - 9ay + 8bx - 12by

= 3a(2x - 3y) + 4b(2x - 3y)

= (3a + 4b)(2x - 3y)
9
Find the equation whose roots are \(\frac{3}{4}\) and -4
A
4x2 - 13x + 12 = 0
B
4x2 - 13x - 12 = 0
C
4x2 + 13x - 12 = 0
D
4x2 + 13x + 12 = 0
CORRECT OPTION: c
Let x = \(\frac{3}{4}\) or x = -4

i.e. 4x = 3 or x = -4

(4x - 3)(x + 4) = 0

therefore, 4x2 + 13x - 12 = 0
10
If m = 4, n = 9 and r = 16., evaluate \(\frac{m}{n}\) - 1\(\frac{7}{9}\) + \(\frac{n}{r}\)
A
1\(\frac{5}{16}\)
B
1\(\frac{1}{16}\)
C
\(\frac{5}{16}\)
D
- 1\(\frac{37}{48}\)
CORRECT OPTION: d
If m = 4, n = 9, r = 16,

then \(\frac{m}{n}\) - 1\(\frac{7}{9}\) + \(\frac{n}{r}\)

= \(\frac{4}{9}\) - \(\frac{16}{9}\) + \(\frac{9}{16}\)

= \(\frac{64 - 258 + 81}{144}\)

= \(\frac{-111}{144}\)

= - 1\(\frac{37}{48}\)
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