1

The rising of a liquid in an open and ended glass tube of narrow bore is

A

osmosis

B

adhesion

C

capillarity

D

surface tension

CORRECT OPTION:
c

2

Which of the following units is equivalent to the watt?

A

kgms^{-2}

B

kgm^{2}s^{-3}

C

kgm^{2}s^{-2}

D

kgm^{2}s^{-1}

CORRECT OPTION:
b

\(Power = \frac{\text{Work done}}{time}\)

= \(\frac{Force \times distance}{time}\)

= \(\frac{mass \times acceleration \times distance}{time}\)

= \(\frac{kg \times m \times m}{s^{2} \times s}\)

= \(kgm^{2} s^{-3}\)

3

Which of the following statements about pressure in a liquid is correct?

A

the pressure in a liquid increases with depth

B

the higher the density of a liquid, the lower the pressure it exerts

C

pressure in liquid act only in a direction perpendicular to the sides of the containing vessel

D

pressure is independent of the acceleration due to gravity

CORRECT OPTION:
a

4

Solid friction, like viscosity is

A

independent of the surface area in contact

B

independent of the relative motion between layers

C

dependent on normal reaction

D

in opposition to motion

CORRECT OPTION:
d

5

The slope of a linear distance-times graph represents

A

acceleration

B

displacement

C

speed

D

velocity

CORRECT OPTION:
c

6

A body of mass 2kg is released from rest on a plane inclined at an angle of 60^{o} to the horizontal. Calculate the acceleration of the body down the plane.[g = 10ms^{-2}]

A

3.1ms^{-2}

B

5.2ms^{-2}

C

6.0ms^{-2}

D

8.7ms^{-2}

CORRECT OPTION:
d

a = g sin \(\theta\)

= 10 sin 60

= 8.7 ms^{-2}

= 10 sin 60

= 8.7 ms

7

The total area under a force-velocity graph represents

A

energy

B

momentum

C

power

D

pressure

CORRECT OPTION:
a

8

A body of mass 20g projected vertically upwards in vacuum returns to the point of projection after 1.2s. [g = 10ms^{-2}]. Calculate the speed of projection

A

1.2ms^{-1}

B

6.0ms^{-1}

C

12.0ms^{-1}

D

0.6ms^{-1}

CORRECT OPTION:
b

V = u - gt

u = v + gt

= 0 + 10 x 0.6

= 6ms^{-2}

u = v + gt

= 0 + 10 x 0.6

= 6ms

9

A body of mass 20g projected vertically upwards in vacuum returns to the point of projection after 1.2s. [g = 10ms^{-2}]. Determine the potential energy of the body at the maximum height of its motion

A

0.36J

B

0.72J

C

360.00J

D

720.00J

CORRECT OPTION:
a

P.E at max = K.E on projection

= \(\frac{1}{2}\)mv^{2} = \(\frac{1}{2} \times 0.02 \times 6^2 = 0.36J\)

= \(\frac{1}{2}\)mv

10

The maximum displacement on either side of the equilibrium position of an object in simple harmonic motion represents

A

period

B

amplitude

C

wavelength

D

frequency

CORRECT OPTION:
b

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