# 2014 - WAEC Physics Past Questions & Answers - page 1

1
A ball falling through a viscous liquid is acted upon by
A
upthrust only
B
upthrust and the ball's weight
C
the ball's weight and viscous force
D
upthrust, the ball's weight and viscous force
CORRECT OPTION: d
2
An object of mass m moves with a uniform speed v round a circular path of radius. If its angular speed is $$\omega$$, the magnitude of the centripetal force acting on it is
A
$$m \omega^2 r$$
B
$$\frac{mv^2}{r}$$
C
$$m \omega r$$
D
$$\frac{mv^2}{r^2}$$
CORRECT OPTION: b
3
When an elastic material is stretched by a force, the energy stored in it is
A
kinetic
B
potential
C
thermal
D
electrical
CORRECT OPTION: b
4
When the linear momentum of a body is constant, the net force acting on it
A
is zero
B
increases
C
decreases
D
remains constant
CORRECT OPTION: a
5
If no net force acts on an object, the object maintains a state of rest or constant speed in a straight line. The above is a statement of Newton's
A
first law of motion
B
second law of motion
C
third law of motion
D
law of universal gravitation
CORRECT OPTION: a
6
Which of the following pairs of physical quantities is made up of vectors?
A
speed and displacement
B
mass and force
C
dislacement and acceleration
D
momentum and length
CORRECT OPTION: c
7
The knowledge of surface tension is applied in the following areas except in
A
manufacturing of rain coats
B
production of palm oil
C
floating of a needle on water
D
washing of plates with soapy water
CORRECT OPTION: b
8
A body is projected vertically upwards with a speed of 10 ms-1 from a point 2m above the ground. Calculate the total time taken for the body to reach the ground. [g = 10ms-2]
A
1.00s
B
2.00s
C
2.18s
D
3.00s
CORRECT OPTION: b
T = $$\frac{2u}{g} = \frac{2 \times 10}{10} = 2s$$
9
A car starts from rest and covers a distance of 40m in 10s. Calculate the magnitude of its acceleration
A
0.25ms-2
B
0.80ms-2
C
3.20ms-2
D
4.00ms-2
CORRECT OPTION: b
S = ut + $$\frac{1}{2} at^2$$

40 = 0 x 10 + $$\frac{1}{2}$$ x a x 102

50a = 40

a = $$\frac{40}{50}$$

= 0.8ms-2
10
The diagram above illustrates a uniform metre rule which is balanced on a pivot by some masses. Calculate the value of M
A
500.0g
B
400.0g
C
44.4g
D
25.0g
CORRECT OPTION: d
clockwise moment = Anti-clock wise moment

= M x 40 = 100 x 10

M = $$\frac{1000}{40}$$

= 25g
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