Question on: JAMB Chemistry - 2014
16.55g of lead (ll) trioxonitrate (V) was dissolved in 100g of distilled water at 20oC, calculate the solubility of the solute in moldm-3
[Pb = 207, N = 14, O = 16]
A
0.05 g
B
2.00 g
C
1.00 g
D
none of the above
Ask EduPadi AI for a detailed answer
Correct Option: D
molar mass of pb (N0 3) 2 = 331
Mole = (\frac{16.55}{331})= 0.05 mole
∴0.05mole pb (No3)2 dissolved in 1000g H2O x = (\frac{0.05x1000}{100})= 0.05 mole /dm 3
Add your answer
Please share this, thanks!
No responses