A ray of light is incident on an equilateral tr... - JAMB Physics 2003 Question
A ray of light is incident on an equilateral triangular glass prism of refractive index 3/2, Calculate the angle through which the ray is minimally deviated in the prism
A
30.0\(^{\circ} \)
B
37.2\(^{\circ} \)
C
42.0\(^{\circ} \)
D
48.6\(^{\circ} \)
correct option: b
For the equilateral glass prism A = 600
\( \frac{3}{2} \text{Sin} \frac{\left( \frac{Dm + 60}{2}\right)}{\left(\frac{60}{2}\right)}= \frac{\left( \text{ Sin }\frac{Dm + 60}{2} \right)}{0.5} \\
\implies Dm = 37.2^{\circ} \)
\( \frac{3}{2} \text{Sin} \frac{\left( \frac{Dm + 60}{2}\right)}{\left(\frac{60}{2}\right)}= \frac{\left( \text{ Sin }\frac{Dm + 60}{2} \right)}{0.5} \\
\implies Dm = 37.2^{\circ} \)
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