A sector of a circle of radius 14cm containing ... - WAEC Mathematics 2007 Question
A sector of a circle of radius 14cm containing an angle 60o is folded to form a cone. Calculate the radius of the base of the cone.
A
\(5\frac{1}{2}cm\)
B
\(4\frac{2}{3}cm\)
C
\(3\frac{1}{2}cm\)
D
\(2\frac{1}{3}cm\)
correct option: d
\(r=\frac{\theta \times l}{360^{\circ }}\
r=?, \theta =60^{\circ }\), l = radius of the orginal sector of a circle = 14cm
\(r=\frac{60\times 14}{360}=\frac{7}{3}=2\frac{1}{3}cm\)
r=?, \theta =60^{\circ }\), l = radius of the orginal sector of a circle = 14cm
\(r=\frac{60\times 14}{360}=\frac{7}{3}=2\frac{1}{3}cm\)
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