An explosion occurs at an altitude of 312 m abo... - JAMB Physics 2023 Question

The speed of sound (\(v\)) can be calculated using the formula:

\[v = v_0 + 0.6t\]

where:
- \(v_0\) is the velocity of sound at \(0^\circ C\),
- \(t\) is the air temperature in degrees Celsius.

Given that \(v_0 = 331 \, \text{m/s}\) and the air temperature (\(t\)) is \(-10.00^\circ C\), we can substitute these values to find \(v\):

\[v = 331 + 0.6 \times (-10) = 331 - 6 = 325 \, \text{m/s}\]

The time (\(t\)) it takes for the sound to reach the ground can be calculated using the formula:

\[v = \frac{d}{t}\]

where:
- \(d\) is the distance (altitude of the explosion),
- \(t\) is the time.

Solving for \(t\):

\[t = \frac{d}{v}\]

Given that \(d = 312 \, \text{m}\) and \(v = 325 \, \text{m/s}\), substitute these values:

\[t = \frac{312}{325} \approx 0.96 \, \text{s}\]

Therefore, the correct answer is: 0.96s