Question on: JAMB Mathematics - 2005
Find the derivative of y = sin(2x3 + 3x - 4)
A
cos (2x3 + 3x - 4)
B
-cos (2x3 + 3x - 4)
C
(6x2 + 3) cos (2x3 + 3x - 4)
D
-(6x2 + 3) cos (2x3 + 3x - 4)
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Correct Option: C
y = sin (2x3 + 3x - 4)
let u = 2x3 + 3x - 4
∴du/dx = 6x2
y = sin U
dy/du = cos U
dy/dx = du/dx * dy/dy
∴dy/dx = (6x2 + 3) cos U
= (6x2 + 3)cos(2x3 + 3x - 4)
let u = 2x3 + 3x - 4
∴du/dx = 6x2
y = sin U
dy/du = cos U
dy/dx = du/dx * dy/dy
∴dy/dx = (6x2 + 3) cos U
= (6x2 + 3)cos(2x3 + 3x - 4)
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