Question on: JAMB Mathematics - 2009
Find the locus of a particle which moves in the first quadrant so that it is equidistant from the lines x = 0 and y = 0 (where k is a constant)
A
x + y = 0
B
x - y = 0
C
x + y + k = 0
D
x - y - k = 0
Ask EduPadi AI for a detailed answer
Correct Option: B
Locus of a particle which moves in the first quadrant so that it is equidistant from the lines
X = 0 and Y = 0 and x = 0 and y = 0 are the x and y axes is the lines bisecting the angle between x and y axes
Add your answer
Please share this, thanks!
No responses