Question on: WAEC Mathematics - 1998
Find the root of the equation 2x\(^2\) - 3x - 2 = 0
A
x = -2 or 1/2
B
x = -2 or1
C
x = -2 or 2
D
x = -1 or 2
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Correct Option: E
2x\(^2\) - 3x - 2 = 0
2x\(^2\) - 4x + x - 2 = 0
2x(x - 2) + 1(x - 2) = 0
(2x + 1)(x - 2) = 0
x = \(\frac{-1}{2}\) or x = 2
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