Given the following balanced chemical equation ... - SS2 Chemistry Chemical Equilibrium Question

To calculate the value of Kc, we use the equilibrium concentrations of the reactants and products. Kc is calculated by taking the product of the concentrations of the products, each raised to the power of their respective stoichiometric coefficients, divided by the product of the concentrations of the reactants, each raised to the power of their respective stoichiometric coefficients.

Kc = ([C]^c x [D]^d) / ([A]^a X [B]^b)

In the given equation, the stoichiometric coefficients are:

a = 2 (for A)

b = 3 (for B)

c = 1 (for C)

d = 1 (for D)

Substituting the given equilibrium concentrations into the equation, we get:

Kc = (0.30¹ x 0.40¹) / (0.50² x 0.80³)

Kc = 0.12 / 2.56

Kc ≈ 0.047

Therefore, the value of the equilibrium constant Kc is approximately 0.047.