Question on: WAEC Mathematics - 2008
If p = (\frac{1}{2}) and (\frac{1}{p - 1} = \frac{2}{p + x}), find the value of x
A
-2\(\frac{1}{2}\)
B
-1\(\frac{1}{2}\)
C
1\(\frac{1}{2}\)
D
2\(\frac{1}{2}\)
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Correct Option: B
p = (\frac{1}{2}; \frac{1}{p - 1} = \frac{2}{p + x})
(\frac{1}{\frac{1}{2} - 1} = \frac{2}{\frac{1}{2} + x})
(\frac{1}{\frac{1 - 2}{2}} = \frac{2}{\frac{1 + 2x}{2}})
(\frac{1}{-\frac{1}{2}} = \frac{2}{\frac{1 + 2x}{2}})
-2 = (\frac{4}{1 + 2x} -2(1 + 2x) = 4)
1 + 2x = (\frac{4}{-2})
1 + 2x = -2
2x = -2 - 1
2x = -3
x = -(\frac{3}{2})
x = -1(\frac{1}{2})
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