If P frac Q R - T 15 frac 1 3 make T the subjec... - JAMB Mathematics 2018 Question
If P = [\(\frac{Q(R - T)}{15}\)] \(\frac{1}{3}\) make T the subject of the relation
A
T = \(\frac{R + P^3}{15Q}\)
B
T = \(\frac{R - 15P^3}{Q}\)
C
T = \(\frac{R - 15P^3}{Q}\)
D
T = \(\frac{15R - Q}{P^3}\)
correct option: c
Taking the cube of both sides of the equation give
P\(^3\) = \(\frac{Q(R - T)}{15}\)
Cross multiplying
15P\(^3\) = Q(R - T)
Divide both sides by Q
\(\frac{15P^3}{Q}\) = R - T
Rearranging gives
T = R - \(\frac{15P^3}{ Q}\)
= \(\frac{RQ - 15P^3}{Q}\)
Answer is C
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