If the hypotenuse of a right-angled isosceles t... - JAMB Mathematics 2009 Question

sin45^o = (\frac{y}{2})

y = 2 sin45^o

y = 2 ((\frac{1}{\sqrt{2}}))

y = (\frac{2}{\sqrt{2}}) x (\frac{\sqrt{2}}{\sqrt{2}})

y = (\frac{2\sqrt{2}}{2})

y = (\sqrt{2})

Since it is an isosceles triangle

x = (\sqrt{2})

Area of (\Delta) = (\frac{1}{2})bh

= (\frac{1}{2}) x (\sqrt{2}) x (\sqrt{2})

= (\frac{1}{2}) x 2

= 1 cm²