Question on: JAMB Mathematics - 2009
If the hypotenuse of a right-angled isosceles triangle is 2cm , what is the area of the triangle?
A
\(\frac{1}{\sqrt{2}}\) cm2
B
1 cm2
C
\(\sqrt{2}\)cm2
D
2\(sqrt{2}\)cm2
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Correct Option: B
sin45o = (\frac{y}{2})
y = 2 sin45o
y = 2 ((\frac{1}{\sqrt{2}}))
y = (\frac{2}{\sqrt{2}}) x (\frac{\sqrt{2}}{\sqrt{2}})
y = (\frac{2\sqrt{2}}{2})
y = (\sqrt{2})
Since it is an isosceles triangle
x = (\sqrt{2})
Area of (\Delta) = (\frac{1}{2})bh
= (\frac{1}{2}) x (\sqrt{2}) x (\sqrt{2})
= (\frac{1}{2}) x 2
= 1 cm2
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