Question on: JAMB Mathematics - 2007
in a basket, there are 6 grapes, 11 bananas and 13 oranges. If one fruit is chosen at random, what is the probability that the fruit is either a grape or banana?
A
\(\frac{5}{30}\)
B
\(\frac{6}{30}\)
C
\(\frac{11}{30}\)
D
\(\frac{17}{30}\)
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Correct Option: D
Total fruits = 6 + 11 + 13 = 30
prob. (Grape) = \(\frac{6}{30}\) = \(\frac{1}{5}\)
prob. (Banana) = \(\frac{11}{30}\)
prob. (a grape or a banana) = \(\frac{1}{5}\) + \(\frac{11}{30}\)
= \(\frac{17}{30}\)
prob. (Grape) = \(\frac{6}{30}\) = \(\frac{1}{5}\)
prob. (Banana) = \(\frac{11}{30}\)
prob. (a grape or a banana) = \(\frac{1}{5}\) + \(\frac{11}{30}\)
= \(\frac{17}{30}\)
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