Question on: WAEC Mathematics - 2008

The angles of a quadrilateral are (x + 10)o, 2yo, 90o and (100 - y)o, Find y in terms of x

A
y = 160 + x
B
y = 100 + x
C
y = 160 - x
D
y = x - 100
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Correct Option: C

Sum of the angles in a quadrilateral = 360o

(x + 10o) + 2y + 90o + 100 - y = 360o

x + y + 200 = 360o

y = 360 - 200 - x

y = 160 - x

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