Question on: JAMB Physics - 2020
The effect of closing the key K in the circuit shown in the figure above would be to?
increase the current by 0.4A
reduce the current by 0.4A
increase the current by 0.6A
reduce the current by 0.6A
When K is open, the total Resistance = 8 + 2 = 10\(\Omega\)
1 = \(\frac{V}{\Omega}\) = \(\frac{6v}{\Omega}\) = 0.6A
When K is closed, \(\frac{1}{8} + \frac{1}{8} = \frac{1}{\Omega}\)
\(\frac{2}{8} = \frac{1}{\Omega}\)
\(\Omega\) = \(\frac{8}{2}\) = 4\(\Omega\)
\(\Omega\) = \(\frac{8}{2}\) = 4\(\Omega\)
4\(\Omega\) in series with 2\(\Omega\)= 6\(\Omega\)
1 = \(\frac{V}{\Omega}\) = \(\frac{6}{6}\) = 1A
1 - 0.6A = 0.4A
Hence, 0.4A increase
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