The effect of closing the key K in the circuit ... - JAMB Physics 2020 Question

When K is open, the total Resistance = 8 + 2 = 10\(\Omega\)

1 = \(\frac{V}{\Omega}\) =  \(\frac{6v}{\Omega}\) = 0.6A

When K is closed, \(\frac{1}{8} + \frac{1}{8} = \frac{1}{\Omega}\) 

\(\frac{2}{8} = \frac{1}{\Omega}\)

\(\Omega\) = \(\frac{8}{2}\) = 4\(\Omega\)

\(\Omega\) = \(\frac{8}{2}\) = 4\(\Omega\)

4\(\Omega\)  in series with 2\(\Omega\)= 6\(\Omega\)

1 = \(\frac{V}{\Omega}\)  = \(\frac{6}{6}\) = 1A

1 - 0.6A = 0.4A

Hence, 0.4A increase