The interior angle of a regular polygon is five... - JAMB Mathematics 2023 Question
The interior angle of a regular polygon is five times the size of its exterior angle. Identify the polygon.
dodecagon
enneadecagon
icosagon
hendecagon
The relationship between the interior angle (\(I\)) and the exterior angle (\(E\)) of a regular polygon is given by the formula:
\[I = 180^\circ - E\]
Given that the interior angle is five times the size of the exterior angle, we can set up the equation:
\[I = 5E\]
Now, substitute \(180^\circ - E\) for \(I\) in the equation:
\[180^\circ - E = 5E\]
Combine like terms:
\[180^\circ = 6E\]
Solve for \(E\):
\[E = \frac{180^\circ}{6} = 30^\circ\]
So, the exterior angle of the regular polygon is \(30^\circ\).
Now, we know that the exterior angle of a regular polygon is given by \(360^\circ/n\), where \(n\) is the number of sides. Set up the equation:
\[30^\circ = \frac{360^\circ}{n}\]
Solve for \(n\):
\[n = \frac{360^\circ}{30^\circ} = 12\]
So, the polygon has 12 sides, and it is a dodecagon.
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