The sum of the interior angle of pentagon is 6x... - JAMB Mathematics 2020 Question
The sum of the interior angle of pentagon is 6x + 6y. Find y in terms of x.
A
y = 6 - x
B
y = 90 - x
C
y = 120 - x
D
y = 150 - x
correct option: b
Sum of the interior angles = (2n - 4) 90\(^o\)
A pentagon has 5 sides(n), hence, n = 5
Therefore, the sum of interior angles = 6 x 90\(^o\) = 540\(^o\)
6x + 6y = 540\(^o\)
6(x + y) = 540\(^o\)
x + y = \(\frac{540^o}{6}\) = 90\(^o\)
y = 90\(^o\)
y = 90 - x
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