Substitution Method - JSS3 Mathematics Lesson Note
In the substitution method, one equation is solved for one variable in terms of the other and substituted into the second equation.
Example:
Using the same equations:
2π₯+3π¦=8
4π₯β2π¦=2
Step 1: Solve the first equation for π₯:
2π₯=8β3π¦
π₯=8β3π¦
Step 2: Substitute π₯ into the second equation:
4(8β3π¦^2)β2π¦=2
4(4β3π¦^2)β2π¦=2
16β6π¦β2π¦=2
16β8π¦=2
β8π¦=β14
π¦=14/8=1.75
Step 3: Substitute π¦ back into π₯=8β3π¦/2 to find π₯:
π₯=8β3(1.75)/2
π₯=8β5.25/2
π₯=2.75/2
π₯=1.375
Thus,
π₯=1.375 and π¦=1.75 are again the solutions.