2009 - JAMB Mathematics Past Questions and Answers - page 6

7(\frac{1}{12}) - 4(\frac{3}{2}) + 2(\frac{1}{2})

Take care of the whole numbers

7 - 4 + 2 = 5

therefore, 5(\frac{1}{12}) - (\frac{3}{4}) + (\frac{1}{2})

LCM = 12

5(\frac{1 - 9 + 6}{12})

4(\frac{13 - 9 + 6}{12})

= 4(\frac{10}{12})

or = 4(\frac{5}{6})

(\frac{81.81 + 99.44}{20.09 + 36.16})

= (\frac{181.25}{56.25})

= 3.22

Spent (\frac{1}{5}) on books remaining (\frac{4}{5})

spent (\frac{1}{3}) of (\frac{4}{5}) on food

(\frac{4}{5}) x (\frac{1}{3}) = (\frac{4}{15})

therefore, (\frac{4}{5}) - (\frac{4}{15})

= (\frac{12 - 4}{15})

= (\frac{8}{15})

5^{2(x - 1)} x 5^{x + 1} = 0.04

5^{2x - 1} x 5^{x + 1} = (\frac{1}{25})

5^{3x - 1} = 5^-2

3x - 1= -2

3x = -1

therefore, x = -(\frac{1}{3})

log₁₀(10 x 7 x 4)

log₁₀280 = log₁₀10 + log₁₀7 + 2 log 2

= 1 + 0.8451 + 2(0.3010)

= 2.4471

(\frac{5 + \sqrt{7}}{3 + \sqrt{7}}) x (\frac{3 + \sqrt{7}}{3 + \sqrt{7}})

(\frac{15 - 5 \sqrt{7} + 3\sqrt{7} - 7}{9 - 3\sqrt{7} + 3\sqrt{7} - 7

= 4 - 2(\sqrt{7})

X : (n² + 1) = 2, 5, 10, 17, 26

y : 5n = 5, 10, 15, 20, 25

x ∩ y = (5, 10)

P² = (\frac{rs^3}{t})

P²t = rs³

r = (\frac{p^2t}{s^3})

(3x - 4)(5x + 3)

= 15x² - 11x - 12