2005 - JAMB Physics Past Questions and Answers - page 4

31
The electric field intensity in a place where a charge of 10-10c experiences a force of 0.4N is?
A
4.0 x 107 NC-1
B
8.0 x 109 NC-1
C
8.O x 10-12 NC-1
D
4.0 x 109 NC-1
correct option: d

The electric force experienced in an electric field of intensity E is given by:

F = qE: where q = the test charge.

E = F/Q = 0.4/10-10 = 0.4 X 10-10

      = 4.0 X 10<sup>9</sup> NC<sup>-1</sup>
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32
Two charged particles are projected into a region where there is a magnetic field perpendicular to their velocities. if the charges are deflected in opposite directions, which of the following statements is true of the charge?
A
the charge must be of opposite sign
B
positive charges are more in number
C
the charges are electrically neutral
D
the charges are of the same sign
correct option: a

The charge must be opposite in sign, since the positive charges will deflect to the negative plate, and the negative charge to the positive plate

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33
The resistance of a pieces of wire of lenght 20m are crossed-sectional area 8 x 10 6m2is?


[Resistivity of the wire = 4 x 10-7 Ω m]
A
5.0 Ω
B
0.5 Ω
C
10.0 Ω
D
1.0 Ω
correct option: d

since resistance R = p (l)/a

= (4 x 10-7 x 20)/8.0 x 10-6

R = 1.0 Ω

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34
The figure above shows a plot of angles of deviation through a glass prism when light is incident at θ degrees on the prism. The incident angle that produces the minimum deviation is
A
20o
B
18o
C
35o
D
25o
correct option: d
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35
The value of F in the figure above when in equilibrium is
A
10N
B
12N
C
20N
D
27N
correct option: c

F = (\frac{17}{sin 60} = \frac{17}{0.866})

= 20N

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36
In the figure above, the coefficient of static friction is 0.5. If the tension in the string is T, the acceleration of the system in motion is
A
5 ms-2
B
15 ms-2
C
3 ms-2
D
9 ms-2
correct option: a

Normal reaction R = 3 kg x 10 = 30N

coefficient of friction , μ = 0.5

∴ acting frictional force = μR = 30 x 0.5

Pulling/sliding force F = 6kg x 10 = 60N.

∴ Net downward force = ma = 60 - 15.0

=> (3 + 6)a = 45

∴ 9a = 45

a = 5m/s2

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37
If the system above is in equilibrium, the tension in the string Q is
A
11N
B
9N
C
4N
D
6N
correct option: b

If the string is in equilibrium, the the tension in the string Q = 4N + 5N = 9N

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38
In the figure above, the work done by the force of 100N inclined at an angle of 60o to the object dragged horizontally to a distance of 8m is
A
800J
B
600J
C
100J
D
400J
correct option: d

Since the force is inclined at an angle 60o to the horizontal, the effective component of te force along the horizontal is given by F x cos 60o

= 100 x 0.5 = 50N.

∴ work done = F x cos 60 x displacement

= 50 x 8.0m

= 400.0J

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39
In the circuit diagram of a transistor above, the terminal P, Q and R represent
A
EMITTER, BASE and COLLECTOR
B
COLLECTOR, EMITTER and BASE
C
BASE, COLLECTOR and EMITTER
D
BASE, ENITTER and COLLECTOR
correct option: a

The fig above shows a conventional transistor, showing the three basic features, the Base, the Emitter and the collector. Thus comparing this with the figure in the question it implies that P = Emitter, Q = Base and R = collector

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40
\( ^{235} _{92}U + ^1 _0n → ^{144} _{56}Ba + ^{90} _{36}Kr +2X \)

In the reaction above, X is
A
electron
B
proton
C
neutrino
D
neutron
correct option: d

235U + 1n → 144Ba + 90Kr + 2x9205636

In the reaction above, balancing the left with the right, show that X is neutron

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