235 92 U 1 0n 144 56 Ba 90 36 Kr 2X In the reac... - JAMB Physics 2005 Question
\( ^{235} _{92}U + ^1 _0n → ^{144} _{56}Ba + ^{90} _{36}Kr +2X \)
In the reaction above, X is
In the reaction above, X is
A
electron
B
proton
C
neutrino
D
neutron
correct option: d
235U + 1n → 144Ba + 90Kr + 2x9205636
In the reaction above, balancing the left with the right, show that X is neutron
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