2021 - JAMB Physics Past Questions and Answers - page 2

11

A boy standing some distance from the foot of a tall cliff claps his hands and hears an echo 0.5s later. If the speed of sound is 340ms\(^{-1}\), how far is he from the cliff?

A

680m

B

170m

C

34m

D

85m

correct option: d

V = \(\frac{2d}{t}\) 
v = 340ms\(^{-1}\)
t = 0.5s
d= ?

d = \(\frac{2d}{2} = \frac{340 \times 0.5}{2}\) = 85m

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12

Which of the following is not a vector quantity?

A

momentum

B

force

C

temperature

D

displacement

correct option: c

Vector quantities are physical quantities characterized by the presence of both magnitude and direction. Examples of vector quantities are displacement, force, torque, momentum, acceleration, velocity, etc.

Scalar is a physical quantity that is completely described by its magnitude. Examples of scalars are speed, density, volume, energy, mass, time, etc.

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13

Calculate the heat energy required to vaporize 50g of water initially at 80ºC if the specific heat capacity of water is 4.23jg\(^{-1}\)k\(^{-1}\) (specific latent heat of vaporization of water is 2260jg\(^{-1}\)

A

530000J

B

23200J

C

17200J

D

130000J

correct option: d

H = mc\(\bigtriangleup\theta\) + mL

m = 50g, c = 4.23J/gk,L = 2260, \(\bigtriangleup\theta\) = 80ºC

H = 50 [4.23 x 80 + 2260]

= 129920 \(\approx\) 130,000J

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14

In a series R-L-C circuit at resonance, the voltages across the resistor and the inductors are 30V and 40V respectively. What is the voltage across the capacitor?

A

30V

B

40V

C

50V

D

70V

correct option: b

AT resonance; X\(_{L}\) = X\(_{c}\)

V\(_{L}\) = V\(_{c}\) = 40V

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15

If the frequency of an emitted x-ray is 1.6 x 10\(^{16}\)Hz, the accelerating potential is?

 [e = 1.6 x 10\(^{-19}\)J, h = 6.63 x 10-\(^{34}\)Js]

A

6630.0V

B

663.0V

C

66.3V

D

6.6V

correct option: c

Given:

f = 1.6 x10\(^{16}\)H\(_{3}\)

h = 6.63 x 10\(^{-39}\)Js

e = 1.6 x 10\(^{-19}\)C, V = ?

V = \(\frac{w}{e} = \frac{hf}{e}\) 

= \(\frac{1.6 \times 10^{16} \times 6.63 \times 10^{34}}{1.6 \times 10^{-19}}\)

= 66.3V

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16

If the fraction of the atoms of radioactive material left after 120 years is 1/64, what is the half-life of the material?

A

24 years

B

20 years

C

10 years

D

2 years

correct option: b

Given fraction of the atoms left = \(\frac{1}{64}\)

= \(\frac{1}{64} = \frac{1}{(2)^{6}}\)

\(\therefore\) = \(\frac{120 \text {years}}{6}\) = 20 years

\(\Rightarrow\) T\(\frac{1}{2}\)

= 20 years

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17

A certain radioactive source emits radiation that was found to be deflected by both magnetic and electric fields. The radiation is?

A

beta rays

B

gamma rays

C

x-rays

D

ultra-violet rays

correct option: a

Because Alpha is positively charged and Beta is negatively charged, they are deflected in an electric or magnetic field, whereas Gamma radiations are not charged and as a result do not deflect in an electric or magnetic field.

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18

The inner diameter of a test tube can be measured accurately using a?

A

micrometer screw gauge

B

pair of dividers

C

meter rule

D

pair of vernier calipers

correct option: d

Vernier callipers are used to measure the internal and external diameters of a tube

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19

Two bodies have masses in the ratio3:1. They experience forces which impart to them, acceleration in the ratio 2:9 respectively. Find the ratio of forces the masses experienced

A

1:4

B

2:1

C

2:3

D

2:5

correct option: c

Given: \(\frac{m_{1}}{m_{2}} = \frac{3}{1}\) \(\Rightarrow\) m\(_{1}\) = 3m\(_{2}\)

\(\frac{a_{1}}{a_{2}} = \frac{2}{9}\) = a\(_{1}\) = \(\frac{2a_{2}}{9}\)

\(\frac{F_{1}}{F_{2}}\) = ?

F = ma

\(\Rightarrow\)  \(\frac{F_{1}}{F_{2}} = \frac{m_{1}a_{1}}{m_{2}a_{2}}\)

= \(\frac{(3 \not m_{2})(2 \not a_{2})}{\not m_{2} a_{2} \not a_{3}}\)

\(\frac{F_{1}}{F_{2}} = \frac{2}{3}\) \(\Rightarrow\) 2:3

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20

Particles of mass 10\(^{-2}\)kg is fixed to the tip of a fan blade which rotates with angular velocity of 100rad\(^{-1}\). If the radius of the blade is 0.2m, the centripetal force is?

A

2N

B

20N

C

200N

D

400N

correct option: b

Given:

m = 10\(^{-2}\)
w = 100rads\(^{-1}\)
F = mw\(^{2}\)r
r = 0.2m

= 10\(^{-2}\) x (100)\(^{2}\) x 0.2

= 20N

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