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Solutions and Concentration - SS1 Chemistry Past Questions and Answers - page 3

21

Which concentration unit is defined as the number of moles of solute per kilogram of solvent?

 

A

Molarity

 

B

Molality

 

C

Mass percentage

 

D

Mole fraction

correct option: b
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22

Which concentration unit is expressed as the ratio of the mass of solute to the total mass of the solution, multiplied by 100?

 

A

Molarity

 

B

Molality

 

C

Mass percentage

 

D

Mole fraction

correct option: c
Users' Answers & Comments
23

Which concentration unit is defined as the ratio of the moles of a component to the total number of moles in the solution?

 

A

Molarity

 

 

B

Molality

 

C

Mass percentage

 

D

Mole fraction

correct option: d
Users' Answers & Comments
24

Which concentration unit is temperature-dependent?

 

A

Molarity

 

B

Molality

 

C

Mass percentage

 

D

Mole fraction

correct option: b
Users' Answers & Comments
25

Which concentration unit is independent of temperature?

 

A

Molarity

 

B

Molality

 

C

Mass percentage

 

D

Mole fraction

correct option: a
Users' Answers & Comments
26

Which concentration unit is commonly used in colligative property calculations?

 

A

Molarity

 

B

Molality

 

C

Mass percentage

 

D

Mole fraction

correct option: b
Users' Answers & Comments
27

Which concentration unit is useful for expressing the concentration of solutes in solid-liquid solutions?

 

A

Molarity

 

B

Molality

 

C

Mass percentage

 

D

Mole fraction

correct option: c
Users' Answers & Comments
28

Which concentration unit is frequently used in gas phase mixtures?

 

A

Molarity

 

B

Molality

 

C

Mass percentage

 

D

Mole fraction

correct option: d
Users' Answers & Comments
29

Which concentration unit takes into account the solvent's mass rather than its volume?

 

A

Molarity

 

B

Molality

 

C

Mass percentage

 

D

Mole fraction

correct option: b
Users' Answers & Comments
30

What is the molarity of a solution containing 25 grams of NaCl dissolved in 500 mL of water?

Step 1: Convert the given mass of NaCl to moles.

Molar mass of NaCl = 22.99 g/mol (sodium) + 35.45 g/mol (chlorine) = 58.44 g/mol

Number of moles of NaCl = Mass of NaCl / Molar mass of NaCl

= 25 g / 58.44 g/mol

≈ 0.428 mol

 

Step 2: Convert the given volume of water to litres.

Volume of water = 500 mL = 500/1000 L = 0.5 L

 

Step 3: Calculate molarity using the formula:

Molarity (M) = Number of moles of solute / Volume of solution (in litres)

= 0.428 mol / 0.5 L

= 0.856 M

The molarity of the solution is 0.856 M.

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