Motion 1 - SS1 Physics Past Questions and Answers - page 3
On a distance-time graph, a curved line represents:
An object at rest
An object moving with constant speed
An object accelerating
An object changing direction.
Refer to the distance-time graph below. What is the average speed of the object during the first 4 seconds?
To calculate average speed, we divide the total distance travelled by the total time taken.
Total distance = 10 metres (from the graph)
Total time = 4 seconds (from the graph)
Average speed = Total distance / Total time
Average speed = 10 metres / 4 seconds
Average speed = 2.5 m/s
Refer to the speed-time graph below. What is the total distance travelled by the object during the first 6 seconds?
To calculate the total distance travelled, we need to find the area under the speed-time graph. In this case, it is a triangle.
Base = 6 seconds (from the graph)
Height = 20 m/s (from the graph)
Area of the triangle = (1/2) X base X height
Area of the triangle = (1/2) X 6 seconds X 20 m/s
Area of the triangle = 60 metres
Therefore, the total distance travelled by the object during the first 6 seconds is 60 meters.
Refer to the distance-time graph below. What is the acceleration of the object between 6 seconds and 10 seconds?
Acceleration can be calculated using the formula:
Acceleration = Change in velocity / Change in time
From the graph, we can see that the object's velocity remains constant between 6 seconds and 10 seconds. Therefore, there is no change in velocity, and the acceleration is zero.