1994 - WAEC Mathematics Past Questions and Answers - page 2

4.95m - 4.8m = 0.15m

\(\frac{0.15}{4.8} \times 100%\)

= \(\frac{25}{8}\)

= \(3\frac{1}{8} %)

\(T_{n} = a + (n - 1) d\) (terms of an A.P)

\(T_{1} = a\)

\(T_{2} = a + d\)

\(T_{10} = a + 9d\)

\(a + a + d = 2a + d = 4 ... (i)\)

\(a + 9d = 19 ... (ii)\)

(ii) x 2: \(2a + 18d = 38 ... (iii)\)

(iii) - (i) : \(17d = 34 \implies d = 2\) 

\(2a + 2 = 4 \implies 2a = 2\)

\(a = 1\)

\(T_{5} + T_{6}\)

= \((a + 4d) + (a + 5d)\)

= \(2a + 9d\)

= \(2(1) + 9(2)\)

= 20

E = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20}

P = {3, 6, 9, 12, 15, 18}

Q = {4, 8, 12, 16, 20}

P' = {1, 2, 4, 5, 7, 8, 10, 11, 13, 14, 16, 17, 19, 20}

P' \(\cap\) Q = {4, 8, 16, 20}

2p - m = 6 ... (i)

2p + 4m = 1 ... (ii)

From (i), m = 2p - 6.

2p + 4(2p - 6) = 1

2p + 8p - 24 = 1

10p = 1 + 24 = 25

p = 2.5

m = 2(2.5) - 6

= 5 - 6

= -1

\(\therefore\) 4p + 3m = 4(2.5) + 3(-1)

= 10 - 3

= 7

8x - 4 = 6x - 10

8x - 6x = -10 + 4

2x = -6

x = -3

\(\therefore\) 5x = 5(-3)

= -15

\(\frac{x^2 + 15x + 50}{x - 5}\)

It is undefined when x - 5 = 0.

That is at x = 5.

4 + 3x < 10

3x < 10 - 4

3x < 6

x < 2

The points P(-2, 3) and Q(2, 7) are on the line.

Gradient of the line = \(\frac{7 - 3}{2 - (-2)}\)

= \(\frac{4}{4}\)

= 1

y = x + b

To find the intercept, we have

7 = 2 + b or 3 = -2 + b.

Solving for b, we get b = 5.

\(\therefore\) The line is y = x + 5.