2001 - WAEC Mathematics Past Questions and Answers - page 5
\(\frac{3}{16}=\frac{4}{x}\
x = \frac{18\times4}{3}=24cm^2\)
∴Area of quadrilateral MPQN
\(=24cm^2 - 18cm^2 = 6cm^2\)
The diagram shows a triangular prism of length 7cm. The right - angled triangle PQR is a cross section of the prism |PR| = 5cm and |RQ| = 3cm. What is the area of the cross-section?
In \(\Delta\) RQP, QR\(^2\) + QP\(^2\) = RP\(^2\)
3\(^2\) + QP\(^2\) = 5\(^2\)
QP\(^2} = 5\(^2\) - 3\(^2\)
QP = \(\sqrt{16}\)
= 4 cm
\(\therefore\) Area = \(\frac{1}{2} \times base \times height\)
= \(\frac{1}{2} \times 3 \times 4\)
= 6 cm\(^2\)
The diagram shows a triangular prism of length 7cm. The right - angled triangle PQR is a cross section of the prism |PR| = 5cm and |RQ| = 3cm. What is the volume of the prism?
Volume of prism = Area x height
In \(\Delta\) RQP, QR\(^2\) + QP\(^2\) = RP\(^2\)
3\(^2\) + QP\(^2\) = 5\(^2\)
QP\(^2} = 5\(^2\) - 3\(^2\)
QP = \(\sqrt{16}\)
= 4 cm
\(\therefore\) Area = \(\frac{1}{2} \times base \times height\)
= \(\frac{1}{2} \times 3 \times 4\)
= 6 cm\(^2\)
Volume = 6 x 7
= 42 cm\(^3\)
A solid cylinder of radius 7cm is 10 cm long. Find its total surface area.
S = \(2\pi r^2 + 2\pi rh\)
= \(2\pi r(r + h)\)
= \(2\pi (7) (7 + 10)\)
= \(238\pi cm^2\)
PQRS is a trapezium in which |PS| = 9cm, |QR| = 15cm, |PQ| = \(2\sqrt{3}, \angle PQR = 90^o and \angle QRS = 30^o\). Calculate the area of the trapezium
The variance of a given distribution is 25. What is the standard deviation?
Given that P = {b, d, e, f} and Q = {a, c, f, g} are subsets of the universal set U = {a,b, c, d, e, f, g}. Find P' ∩ Q
U = {a, b, c, d, e, f, g}
P = {b, d, e, f}
Q = {a, c, f, g}
P' = {a, c, g}
P' \(\cap\) Q = {a, c, g}
What is the length of \(\bar{RP}\)?
The number line represents