2001 - WAEC Mathematics Past Questions and Answers - page 4

Range = 30.5 - 10.5

= 20 years

Total number of students = 20 + 16 + 10 + 6

= 52 students

The size of an exterior angle = \(\frac{360}{n}\)

From the options, all options can perfectly divide 360°, except 21°.

< PQS = 50° (PQ = PR)

< PQS = < SPQ = 50° (QS = PS)

In triangle PSQ, < PQS + < QPS + < PSQ = 180°

50° + 50° + < PSQ = 180°

< PSQ = 180° - 100° = 80°

In \(\Delta\) PRQ, < SRQ = 90° - 58°

< SRQ = < QTS = x (angles in the segment)

\(\therefore\) x = 32°

From the diagram
\(r^2 = B^2 + 15^2\
= 64 + 225\
r = \sqrt{289} = 17cm\)

Perimeter of the sector = \(2r + \frac{\theta}{360} \times 2\pi r\)

= \(2(14) + \frac{135}{360} \times 2 \times \frac{22}{7} \times 14\)

= \(28 + 33\)

= 61 cm