Question on: WAEC Mathematics - 2001
PQRS is a rhombus of side 16cm. The diagonal |QS| = 20cm. Calculate, correct to the nearest degree, ∠PQR
A
51o
B
64o
C
77o
D
103o
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Correct Option: D
cos\(\alpha\) = \(\frac{10}{16}\) = 0.625
\(\alpha\) = cos-1(0.625)
= 51.3o
∠PQR = 2\(\alpha\)
= 2(51.3o)
= 102.6
= 103o
\(\alpha\) = cos-1(0.625)
= 51.3o
∠PQR = 2\(\alpha\)
= 2(51.3o)
= 102.6
= 103o
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