2009 - WAEC Mathematics Past Questions and Answers - page 2

d = 42cm

Circumference = \(\pi d = \frac{22}{7} \times 42cm\)

= 22 x 6cm = 132cm

Total distance covered = circumference x number of revolutions

= 132cm x 16 = 2112cm

(2^x + 5)^o + (x^o + 20^o) + x + (3x - 20)^o + (x + 15)^o = (n - 2) x 180

8n + 20 = (5 - 2) x 180

where n = 5(Pentagon)

8n + 20 = 3 x 180

8n + 20 = 540

8n = 540 - 20

8n = 520

x = 65^o

Locus L = (P : PM = Pn}

For M and N being two fixed points

Since PM = PN, P is equidistant from Mand N, So L must be the perpendicular bisector of the line MN

Sin 60 = \(\frac{\sqrt{3}}{2}\); cos 60^o = \(\frac{1}{2}\)

= \(\frac{1 - \sin 60}{1 + \cos 60} = \frac{1 - \frac{\sqrt{3}}{2}}{1 + \frac{1}{2}}\)

= \(\frac{2 - \sqrt{3}}{3}{2}\div \frac{2 + 1}{2}\)

= \(\frac{2 - \sqrt{3}}{2} \times \frac{2}{3}\)

= \(\frac{2 - \sqrt{3}}{3}\)

\(\frac{x + 50 + 70}{3} = 55\)

x + 120 = 3(55)

x + 120 = 165

= 165 - 120

x = 45%

22 35 41 63 74 82


Median = \(\frac{41 + 63}{2} = \frac{104}{2}\)

= 52

2.7864 x 10^-3 = 0.0027864

= 0.0028(approx. 2 s.f)

9^2x = \(\frac{1}{3}\)(27^x)

(2²)^2x = \(\frac{(3^{3x})}{3}\)

(3^4x) = 3^{3x - 1}

4x = 3x - 1

4x - 3x = -1

x = -1

85% of x = 3230

\(\frac{85}{100} \times x\) = N3230

x = \(\frac{100}{85}\) x N3230

x = N3800.00

1 litre = 1000cm³

1800 litre = 1800 x 1000cm³

l x b x h = capacity

600 x 150 x h = 1800000

h = \(\frac{1800000}{600 \times 150}\)cm

h = 20cm