0 25 mole of hydrogen chloride was dissolved in... - JAMB Chemistry 1999 Question
0.25 mole of hydrogen chloride was dissolved in distilled water and the volume made up of 0.50 dm3. If 15.0 cm3 of the solution requires 12.50 cm3 of aqueous sodium trioxocarbonate (IV) for neutralization, calculate the concentration of the alkaline solution
A
0.30 mol dm3
B
0.40 mol dm3
C
0.50 mol dm3
D
0.60 mol dm3
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Correct Option: A
M1 V1 = M2 V2
∴ Mn Vn represent volume and molar concentration of HCL also MyVy represent volume and molar concentration of Na2CO3
MnVn = MyVy
0.25 * 15 = 12.50 * My
My = (0.25 * 15)/12.50
My = 0.3m/dm3
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