14N 4He 17O X728 In the equation above the part... - JAMB Physics 2008 Question
| 14 | N + | 4 | He → | 17 | O + X |
| 7 | 2 | 8 |
In the equation above, the particles X is
A
a proton
B
a neutron
C
an α - particle
D
a β - particle
correct option: a
for the conversion of mass 14 + 4 = 17 + x
∴ X = 18 - 17 = 1
for conservation pf charge:7 + 2 = 8 + y
y = 9 - 8 = 1
Thus, the element is 11X which is equal to hydrogen nucleus ( proton)
∴ X = 18 - 17 = 1
for conservation pf charge:7 + 2 = 8 + y
y = 9 - 8 = 1
Thus, the element is 11X which is equal to hydrogen nucleus ( proton)
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