Question on: JAMB Chemistry - 2017
(^{226}{88}Ra) → (^x{86}Rn) + alpha particle
A
226
B
220
C
227
D
222
Ask EduPadi AI for a detailed answer
Correct Option: D
(^{226}{88}Ra) → (^x{86}Rn) + (^4_{2}He)
(^4_{2}He) = alpha particle
considering the summation of the mass number
226 = x + 4
x = 226 + 4
x = 222
Add your answer
Please share this, thanks!
No responses