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27 13 Al 1 0 n Rightarrow 24 11 Na X - JAMB Physics 1992 Question

\(^{27}_{13}Al\) + \(^{1}_{0}n\) \(\Rightarrow\) \(^{24}_{11}Na\) + X
A
a proton
B
a gamma ray
C
a helium particle
D
an alpha particle
correct option: d

(^{27}{13}Al) + (^{1}{0}n) (\Rightarrow) (^{24}{11}Na) + (^{b}{a}X)

a + 11 = 0 + 13 (\Rightarrow) a = 2

b + 24 = 1 + 27 (\Rightarrow) b = 4

(^{b}{a}X) = (^{4}{2}\alpha)

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