Question on: JAMB Chemistry - 2022
2H\(_2\) + O\(_2\) → 2H\(_2\)O
From the equation above, calculate the volume of unreacted oxygen gas if a mixture of 50cm\(^3\) of hydrogen and 75cm\(^3\) of oxygen is involved
A
85cm\(^3\)
B
50cm\(^3\)
C
125cm\(^3\)
D
55cm\(^3\)
Ask EduPadi AI for a detailed answer
Correct Option: B
From the given equation, 2 mol H\(_2\) reacted with 1 mol of O\(_2\)
50cm\(^3\) hydrogen reacted with 25cm\(^3\) oxygen
remainder oxygen = supplied amount - reacted amount
=> 75cm\(^3\) - 25cm\(^3\)
= 50cm\(^3\)
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