2SO 2 g O 2 g 2SO 3 g H -395 7kJmol -1 In the e... - JAMB Chemistry 2018 Question
2SO\(_2\) \(_{(g) }\)+ O\(_2\) \(_{(g) }\) ↔ 2SO\(_3\)\(_{(g) }\) ΔH = -395.7kJmol\(^{-1}\)
In the equation, an increase in temperature will shift the equilibrium position to the
A
left and equilibrium constant decreases
B
left and equilibrium constant increases
C
right and equilibrium constant increases
D
right and equilibrium constant decreases
correct option: d
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