Question on: JAMB Chemistry - 2020
8g of CH\(_4\) occupies 11.2 at S.T.P. What volume would 22g of CH\(_3\)CH\(_2\)CH\(_3\) occupy under the same condition?
A
3.7dm\(^3\)
B
11.2dm\(^3\)
C
22.4dm\(^3\)
D
33dm\(^3\)
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Correct Option: B
Here's how to solve this problem:
-
Calculate the molar mass of CH₄:
- C = 12 g/mol
- H = 1 g/mol, and there are 4 H atoms, so 4 * 1 = 4 g/mol
- Molar mass of CH₄ = 12 + 4 = 16 g/mol
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Determine the moles of CH₄:
- Given: 8 g of CH₄
- Moles = mass / molar mass = 8 g / 16 g/mol = 0.5 mol
-
Use the given information to find the volume of 1 mole of a gas at STP: *
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