Question on: JAMB Chemistry - 2020
8g of CH\(_4\) occupies 11.2 at S.T.P. What volume would 22g of CH\(_3\)CH\(_2\)CH\(_3\) occupy under the same condition?
A
3.7dm\(^3\)
B
11.2dm\(^3\)
C
22.4dm\(^3\)
D
33dm\(^3\)
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Correct Option: B
Here's how to solve this problem:
1. **Calculate the molar mass of CH₄:**
* C = 12 g/mol
* H = 1 g/mol, and there are 4 H atoms, so 4 * 1 = 4 g/mol
* Molar mass of CH₄ = 12 + 4 = 16 g/mol
2. **Determine the moles of CH₄:**
* Given: 8 g of CH₄
* Moles = mass / molar mass = 8 g / 16 g/mol = 0.5 mol
3. **Use the given information to find the volume of 1 mole of a gas at STP:**
*
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