Question on: WAEC Physics - 2012
A 120\(\Omega\) resistor dissipates 8 kJ of heat in 20s. Calculate the current through the resistor
A
5.8A
B
6.9A
C
30.0A
D
33.3A
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Correct Option: A
Q = I2Rt
I = \(\sqrt{\frac{Q}{Rt}}\)
= \(\sqrt{\frac{8000}{12 \times 20}}\)
= 5.8
I = \(\sqrt{\frac{Q}{Rt}}\)
= \(\sqrt{\frac{8000}{12 \times 20}}\)
= 5.8
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