A 20kg mass is to be pulled up a slope inclined... - JAMB Physics 2018 Question

V. R = \(\frac{1}{Sinθ}\)

  m = 20kg

  V.R = \(\frac{1}{Sin 30 }\)

  = 2

  Efficiency = 75%

  Load = mg

  = 20 x 10 = 200N

  Efficiency = \(\frac{M.A}{V.R \times 100}\)

  75/100 = \(\frac{M.A}{2}\)

  M .A = 75 x \(\frac{2}{100}\)

  M. A = 1.5

  Since M. A. = \(\frac{\text{Force}}{\text{Load}}\)

  Force = 1.5 x 200

  = 87 N