Question on: JAMB Physics - 1997
A 5kg block is released from rest on a smooth plane inclined at an angle of 30o to the horizontal. What is the acceleration down the plane? [g = 10ms-2]
A
5.0 ms-2
B
5.8 ms-2
C
8.7 ms-2
D
25.0 ms-2
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Correct Option: A
ma = mgsin\(\theta\)
a = \(\frac{5 {\times} 10 {\times} sin30}{t}\)
a = 5ms2
a = \(\frac{5 {\times} 10 {\times} sin30}{t}\)
a = 5ms2
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