A ball is thrown vertically upwards with an ini... - SS1 Physics Motion 2 Question

To find the maximum height reached by the ball, we need to determine the time it takes for the ball to reach its peak and then use that time to calculate the height using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Given:

u = 15 m/s (upwards)

a = -9.8 m/s^2 (acceleration due to gravity)

To find the time taken to reach the peak, we use the equation v = u + at and set v = 0:

0 = 15 m/s - 9.8 m/s2 X t

9.8 m/s2 X t = 15 m/s

t = 15 m/s / 9.8 m/s2

t ≈ 1.53 seconds

Now, to find the maximum height, we use the equation s = ut + 1/2at^2:

s = 15 m/s * 1.53 s + 1/2 * (-9.8 m/s^2) * (1.53 s)^2

s ≈ 11.46 metres

Therefore, the maximum height reached by the ball is approximately 11.46 metres.