Question on: SS1 Physics - Motion 2
A ball is thrown vertically upwards with an initial velocity of 15 m/s. What is the maximum height reached by the ball?
To find the maximum height reached by the ball, we need to determine the time it takes for the ball to reach its peak and then use that time to calculate the height using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
Given:
u = 15 m/s (upwards)
a = -9.8 m/s^2 (acceleration due to gravity)
To find the time taken to reach the peak, we use the equation v = u + at and set v = 0:
0 = 15 m/s - 9.8 m/s2 X t
9.8 m/s2 X t = 15 m/s
t = 15 m/s / 9.8 m/s2
t ≈ 1.53 seconds
Now, to find the maximum height, we use the equation s = ut + 1/2at^2:
s = 15 m/s * 1.53 s + 1/2 * (-9.8 m/s^2) * (1.53 s)^2
s ≈ 11.46 metres
Therefore, the maximum height reached by the ball is approximately 11.46 metres.
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