Question on: SS2 Physics - Mechanics - Laws of Motion
A ball is thrown vertically upwards with an initial velocity of 20 m/s. How high does the ball rise before coming back down? (Take g = 10 m/s2)
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When the ball reaches its highest point, its velocity becomes 0 m/s. Using the equation v2 = u2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration (in this case, -g), and s is the displacement, we can solve for the displacement. Plugging in the values, we get 02 = 202 + 2(-10)s. Solving for s, we get s = 100 m.
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